Question

A number is decreased by 20% and the decreased number is then increased by 20%. Find the net increase or decrease percent.​

Answer 1

Answer:

net increase or decrease is 0.

Step-by-step explanation:

let the no. be x.

the no. decreased by 20% = x- 20/100

the decreased no. increased by 20%

= x-20/100 +20/100 = x.

so, there is no net increase or decrease.

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Answer 2

Answer:

net decrease percent = 4%

Step-by-step explanation:

let the given number be y

Increase number = 120% of y = $(y \times \frac{120}{100} ) = \frac{6y}{5}$

Decreased number = 80% of $\frac{6y}{5 } = ( \frac{6y}{5} \times \frac{80}{100} ) = \frac{24y}{25}$

Net decrease = $(y - \frac{24y}{25} ) = \frac{y}{25}$

Net decrease per cent = $( \frac{y}{25} \times \frac{1}{y} \times 100)$% = 4%

Hence, net decrease percent = 4%