Math, asked by chatrapathi1, 8 months ago

A number is divided in 2 parts such that one part is 10 more than the other if the two parts are In the ratio5:3 find the number of two parts. ​

Answers

Answered by brainlyaryan12
5

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→A number is divided in 2 parts such that one part is 10 more than the other if the two parts are In the ratio5:3 find the number of two parts.

✪  \huge{\underline{\overline{\mathbf{Answer}}}}   ✪

Let first number = x

Second Number = x+10

Ratio of the Number = 5:3

Now According to Question:-

\Large{\frac{x+10}{x}=\frac{5}{3}}

3\times (x+10)= 5\times x {Cross Multiplication}

3x+30=5x

5x-3x=30

x=\frac{30}{2}

x=15

First Number = \large{\pink{\underline{15}}}

Second Number = \large{\pink{\underline{25}}}

Original Number is:-

\huge{\orange{\underline{\overline{40}}}}

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Step-by-step explanation:

Answered by venkatavineela3
0

Answer:

Step-by-step explanation:

let the number be divided in the form of x and y

x=10+y

x/y=5/3

let x=5a

y=3a

now 5a=10+3a

2a=10

a=5

now x=25

y=15

the number is x+y=40

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