Question

A number is divided in 2 parts such that one part is 10 more than the other if the two parts are In the ratio5:3 find the number of two parts. ​

Answer 1

✪ $\huge{\underline{\overline{\mathbf{Question}}}}$   ✪

→A number is divided in 2 parts such that one part is 10 more than the other if the two parts are In the ratio5:3 find the number of two parts.

✪  $\huge{\underline{\overline{\mathbf{Answer}}}}$   ✪

Let first number = x

Second Number = x+10

Ratio of the Number = 5:3

Now According to Question:-

$\Large{\frac{x+10}{x}=\frac{5}{3}}$

⇒$3\times (x+10)= 5\times x$ {Cross Multiplication}

⇒$3x+30=5x$

⇒$5x-3x=30$

⇒$x=\frac{30}{2}$

⇒$x=15$

First Number = $\large{\pink{\underline{15}}}$

Second Number = $\large{\pink{\underline{25}}}$

Original Number is:-

$\huge{\orange{\underline{\overline{40}}}}$

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Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

let the number be divided in the form of x and y

x=10+y

x/y=5/3

let x=5a

y=3a

now 5a=10+3a

2a=10

a=5

now x=25

y=15

the number is x+y=40