A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in rhe ratio 5:3, find the number and the two parts.
Answers
Answered by
8
let the divider be x
5:3 = 5x and 3x
ATQ
5x - 3x = 10
2x = 10
x = 10/2
x = 5
5x = 5 × 5 = 25
3x = 3 × 5 = 15
15 + 25 = 40
5:3 = 5x and 3x
ATQ
5x - 3x = 10
2x = 10
x = 10/2
x = 5
5x = 5 × 5 = 25
3x = 3 × 5 = 15
15 + 25 = 40
Answered by
3
answer is 40 in the number of two parts
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