Question

A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in rhe ratio 5:3, find the number and the two parts.

Answer 1

A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in the ratio 5:3, find the number and the two parts.

solution:
       let one part of number = x
           therefore ,  other part of number = x+10
   according to question ,
             x+10/x=5/3
           3(x+10)= 5x
           3x+30 =5x
             30 = 5x -3x
             30 = 2x
     or x=30/2
         x=15

therefore one part of number = 15
and other part = 15+10 =25

hence number = 15+25 =40

hope this helps you!!!

Answer 2

Answer: One part of number is 15 and other part of number is 15+10=25.

Step-by-step explanation:

Let one part of number= a

Therefore other part of number = a+10

Ratio 5:3 can also written in the form of fraction 5/3

According to question (ATQ)

a+10/a=5/3

3(a+10)=5a

30=5a-3a

30=2a

a=30/2

a=15

Therefore one part of number=15

And other part of number=15+10=25

Hence number=15+25=40...

Hope this will help you....