Question

A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in rhe ratio 12:3, find the number and the two parts.

Answer 1

Here is my assumption:

A number is divided in 2 parts: x and y

x > y by 10... (given)

So we can write: y+10 > y... (substituting x)

y+10. 12

____ = ___

y 3

Cross Multiplying, we get:

3(y+10) = 12(y)

3y + 30 = 12y

30 = 12y - 3y

30 = 9y

y = 30

___ = 3.3333...

9

But No.1 = y+10

hence, 3.3333.. + 10 = 13.3333...

No.2 = y = 3.33333..

Hence 13.333.. + 3.333.. = 16.66666....

Approx = 17