Math, asked by janvibh682, 10 months ago

A number is divided into two parts in such a way that 60% of 1st part is 2 more than the 40% of 2nd part and 60% of the 2nd part is 1 more than the 40% of 1st part. Find the numbers.

Answers

Answered by jinadevkv
0

Answer:

The numbers are 8 and 7

Step-by-step explanation:

let the numbers X and Y

0.6X = 0.4Y + 2    6X = 4Y + 20   X = (4Y + 20)/6

0.4X + 1 = 0.6 Y    4X + 10 = 6Y    4(4Y+20)/6 + 10 = 6Y

16Y/6 + 80/6 + 10 = 6Y

(6 - 16/6) Y = 80/6 + 10

20 Y = 140

Y = 7

ie, X = (4*7 +20)/6 = 48/6 = 8

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