Question

A number is divided into two parts in such a way that 80% of 1st part is 3 more than 60% of 2nd part and 80% of 2nd part is 6 more than 90% of the 1st part. then the number is

Ans: a/q
Let first part be x and second part be Y
80x/100=(60y/100)+3
By solving we get
8x=6y+30----------(I)
Now
80y/100=(90x/100)+6
By solving we get
8y=9x+60-------(ii)
By solving equation (I) & (ii)
We get
X=60
Y=75

Answer 1

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