Question

a number is divided into two parts in such a way
that 80% of the first part is greater than 60% of
the second part by 3 and 80% of the second part
is greater than 90% of the first part by 6 find the
number​

Answer 1

Answer:

The circumference of a circle is 2πr or πD if diameter is given.

The answer is 25.13 cm

C=2πr

So finding for radius in this equation=diameter/2

8/2=4 cm

So now 2 × 22/7 × 4

176/7=25.13 cm

OR

C=πD

22/7 × 8

176/7=25.13 cm

Answer 2

Correct Answer:

Correct Answer:C) 135

Correct Answer:C) 135Description for Correct answer:

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=3

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=38a−6b=308a−6b=30....(i)

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=38a−6b=308a−6b=30....(i)Case : (ii) 80100b−90100a=680100b−90100a=6

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=38a−6b=308a−6b=30....(i)Case : (ii) 80100b−90100a=680100b−90100a=68b−9a=608b−9a=60......(ii)

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=38a−6b=308a−6b=30....(i)Case : (ii) 80100b−90100a=680100b−90100a=68b−9a=608b−9a=60......(ii)From equation (i) and (ii)

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=38a−6b=308a−6b=30....(i)Case : (ii) 80100b−90100a=680100b−90100a=68b−9a=608b−9a=60......(ii)From equation (i) and (ii)a - 60, b = 75

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=38a−6b=308a−6b=30....(i)Case : (ii) 80100b−90100a=680100b−90100a=68b−9a=608b−9a=60......(ii)From equation (i) and (ii)a - 60, b = 75Hence required number = (a + b)

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=38a−6b=308a−6b=30....(i)Case : (ii) 80100b−90100a=680100b−90100a=68b−9a=608b−9a=60......(ii)From equation (i) and (ii)a - 60, b = 75Hence required number = (a + b)= (60 + 75)

Correct Answer:C) 135Description for Correct answer:Let the first and second part of a number is a and b respectively.According to the question,Case : (i)80100a−60100b=380100a−60100b=38a−6b=308a−6b=30....(i)Case : (ii) 80100b−90100a=680100b−90100a=68b−9a=608b−9a=60......(ii)From equation (i) and (ii)a - 60, b = 75Hence required number = (a + b)= (60 + 75)= (135)

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