Question

a number is divided into two parts in such a way that 80 of 1st part is 3 more than 60 % of 2nd part and 80% of 2nd part is 6 more than 90% of the first part.then the number is

Answer 1

80/100*x+90/100*x-3=60/100*x+3+80/100*x
9x/10-3=6x/10+3
x=60/3=20

Answer 2

Dear Student,

◆ Answer -

N = 135

● Explanation -

Let N be the number divided into x and y.

From given conditions,

80% of x = 60 % of y + 3

80/100 × x = 60/100 × y + 3

4x/5 = 3y/5 + 3

4x = 3y + 15 ...(1)

Also,

80% of y = 90% of x + 6

80/100 × y = 90/100 × x + 6

4y/5 = 9x/10 + 6

8y = 9x + 60 ...(2)

Solving (1) and (2),

x = 60

y = 75

Required number is

N = x + y

N = 60 + 75

N = 135

Hence, required no is 135.

Thanks dear. Hope this helps you...