Question

A number is divided into two parts so that the difference of the parts is 40. If four-fifth of the smaller part exceeds one-third of the greater part by 24. Find the number​

Answer 1

$\tt\large\underline\purple{Let:-}$

• $\sf{The\: smaller\:part=x}$
• $\sf{The\: greater\:part=x + 40}$

$\tt\large\underline\purple{To\:Find:-}$

• $\sf{The\:smaller\: number=?}$
• $\sf{The\: greater\: number=?}$

$\tt\large\underline\purple{Solution:-}$

To calculate the required number at first we have to set up equation. Before calculating we have to assume the smaller part be x and the greater part = ? here we will solve the greater part. As given in the question that the difference between two parts = 40 , so set equation here like this . The greater part - smaller part = 40 => greater part - x = 40 so, the greater part = x + 40.

$\tt\large\underline{As\:per\:the\: question:-}$

$\tt\small{\implies 4/5th\:_{(smaller\:no)} = 1/3th\:_{(greater\:no)}+24}$

$\sf{\implies \dfrac{4x}{5}=\dfrac{x + 40}{3} + 24}$

$\sf{\implies \dfrac{4x}{5}-\dfrac{x + 40}{3} = 24}$

$\sf{\implies \dfrac{12x-5x-200}{15}=24}$

$\sf{\implies \dfrac{7x-200}{15}=24}$

$\sf{\implies 7x - 200 = 360}$

$\sf{\implies 7x = 360 + 200}$

$\sf{\implies 7x = 560}$

$\sf{\implies x = 80}$

$\sf\small\underline\pink{Hence,\:the\: smaller\: number\:(x)=80:-}$

$\sf\small\underline\pink{Hence,\:the\: greater\: number\:(x+40)=120:-}$

Answer 2

Step-by-step explanation:

given :

• A number is divided into two parts so that the difference of the parts is 40. If four-fifth of the smaller part exceeds one-third of the greater part by 24. Find the number

to find :

• Find the number

solution :

• the answer in attachment please check

answer :

• number is divided two parts = 80 and 120