A number is divided into two parts so that the difference of the parts is 40. If four-fifth of the smaller part exceeds one-third of the greater part by 24. Find the number .
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Answer:
The required number is 200
Step-by-step explanation:
Let the number be X
The two parts of the numbers are Y and Y+40
As per the question:-
4Y/5 - 24 = (Y+40)/3
(4Y - 120)/5 = (Y+40)/3
3(4Y-120) = (Y+40)/3
12Y - 360 = 5Y + 200
12Y - 5Y = 200+360
7Y = 560
Y = 80
Now,
X = Y + (Y + 40)
X = 80 + 80 + 40
X = 200
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