a number is divided into two parts such that one part is 10 more than the other . if the two parts are in the ratio 5:3 , find the number and the two parts.
Answers
Answered by
46
Solution :-
Let the one number be x.
Other number = x + 10.
According to the question,
=> (x + 10)/x = 5/3
=> 3(x + 10) = 5x
=> 3x + 30 = 5x
=> 3x - 5x = - 30
=> - 2x = - 30
=> x = - 30/-2 = 15
Therefore,
One number = x = 15
Other number = x + 10 = 15 + 10 = 25
So, Sum of both the number = (15 + 25) = 40
Answered by
16
Heyaa mate !!!
Here is your answer :-
Let one number be x.
Other number = x + 10.
According to the question,
=> (x + 10)/x = 5/3
=> 3(x + 10) = 5x
=> 3x + 30 = 5x
=> - 2x = - 30
=> x = - 30/-2
=> x = 15
So,
One number = x = 15
Other number = x + 10 = 15 + 10 = 25
Therefore ,
Sum of both the number = (15 + 25) = 40
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