Question

a number is divided into two parts such that one part is 10 more than the other. if the two parts are in the ratio 5 is to 3, find the number and the two parts.​

Answer 1

Step-by-step explanation:

1st=5x

2nd=3x

Diff =2x=10(given) x=5

1st=5×5=25

2nd=5×3=15

Answer 2

$\huge\sf\pink{Answer}$

☞ Number = 40

☞ First Part = 15

☞ Second Part = 25

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ A number is divided into two parts

✭ One part is 10 more than other

✭ Two parts are in ratio 5:3

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◈ The two numbers and the two parts

$\rule{110}1$

$\huge\sf\purple{Steps}$

Let us assume that,

◕ First part = x

◕ Second part x+10

$\bullet\:\underline{\textsf{As Per the Question}}$

$\sf{\dashrightarrow \dfrac{x+10}{x}=\dfrac{5}{3}}$

$\sf{\dashrightarrow 3(x+10)=5\times x }$

$\sf{\dashrightarrow 3x+30=5x}$

$\sf{\dashrightarrow 5x-3x=30}$

$\sf{\dashrightarrow 2x=30}$

$\dashrightarrow\sf{x= {\dfrac{30}{2}}}$

$\orange{\sf{\dashrightarrow x =15}}$

So Now,

≫ First part = x = 15

≫ Second part = x+10 = (15+10) = 25

≫ Number = x+x+10 = (15+15+10) = 40

$\rule{170}3$