Question

A number is divided into two parts such that one part is 10 more than the other. If the two
parts are in the ratio 5:3, find the number and the two parts.
When I triple a certain number and add 2, I get the same answer as I do when I subtract​

Answer 1

A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in the ratio 5:3, find the number and the two ?

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solution:

let one part of number = x

therefore , other part of number = x+10

according to question ,

x+10/x=5/3

3(x+10)= 5x

3x+30 =5x

30 = 5x -3x

30 = 2x

or x=30/2

x=15

therefore one part of number = 15

and other part = 15+10 =25

hence number = 15+25 =40

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Answer 2

$\huge{\green{\underline{\underline{\textsf{\green{Answer}}}}}}$

$\sf{Let \:one\: part \:of \:the \:number \:be\: x}$

$\sf{then,\: the\: other \:part\: be \:x+10}$

$\sf{According \:to\: the\: condition,\: in\: the\: question,}$ $\sf{we\: get}$

$\sf{⇒ \dfrac{x+10}{x}}$

$\sf{⇒3x+30=5x}$

$\sf{⇒2x=30}$

$\sf{⇒x=15}$

$\sf{Therefore, }$

$\sf{x+10= 15+10 = 25}$

$\sf{then, \:the\: new \:number = 15+25=40}$

$\sf{Hence, \: the \: two \: parts \: of \: a \: numbers \: are \: 15}$ $\sf{and \: 25 \: and \: the \: number \: is \: 40}$