a number is divided into two parts such that one part is 10 more than the other two parts in the ratio 5:3 find the number
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A number is divided into two parts such that one part is 10 more than the other. if the two parts are in the ratio 5:3,find the number and the two parts
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Answered by
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the number should be 40...
let one part be x
so other part is x+10
as given
x/x+10 =3/5
5x = 3x + 30
5x-3x = 30
2x = 30
x =15
so first part is 15
and second part will be 15+10=25
the number should be 15 + 25 = 40
let one part be x
so other part is x+10
as given
x/x+10 =3/5
5x = 3x + 30
5x-3x = 30
2x = 30
x =15
so first part is 15
and second part will be 15+10=25
the number should be 15 + 25 = 40
how came 30 here
multiply 3×10
you have to multiply 3 with (x + 10)
OK thanks
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Answered by
1
number is 2515 . first part 25 is 10 more than other part 15. and they 25:15= 5:3.
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