Question

A number is divided into two parts, such that one part is 10 more than the other. If the 2 parts are in the ratio of 5:3 find the number and the 2 parts

Answer 1

Answer:

25+15=40

Step-by-step explanation:

Let the two parts be x&y

We have:

x=y+10

x/y=5/3 => 3x=5y =>3(y+10)=5y => 2y=30 => y=15

x=y+10=15+10=25

So we got, two parts of the number: 25&15 and the number itself =40

Answer 2

$\huge{\green{\underline{\underline{\textsf{\green{Answer}}}}}}$

$\sf{Let \:one\: part \:of \:the \:number \:be\: x}$

$\sf{then,\: the\: other \:part\: be \:x+10}$

$\sf{According \:to\: the\: condition,\: in\: the\: question,}$ $\sf{we\: get}$

$\sf{⇒ \dfrac{x+10}{x}}$

$\sf{⇒3x+30=5x}$

$\sf{⇒2x=30}$

$\sf{⇒x=15}$

$\sf{Therefore, }$

$\sf{x+10= 15+10 = 25}$

$\sf{then, \:the\: new \:number = 15+25=40}$

$\sf{Hence, \: the \: two \: parts \: of \: a \: numbers \: are \: 15}$ $\sf{and \: 25 \: and \: the \: number \: is \: 40}$