Question

A number is divided into two parts such that one part is 10 more than the other. If the two are in the ratio 5:3, find the number and the two parts.​

Answer 1

Answer:

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Step-by-step explanation:

Let the parts be x and y

Thus, x+10=y - - - - - - >(1)

Now, let the ratio is

5/3=x/y. . . . . . (cross multiplying)

Hence, 5y=3x ---------->(2)

Putting (1) in (2)

Hence, 5(x+10)=3x

5x+50=3x

2x=-50

x=-25

Hence, y=-25+10=-15

Hence the no. is= (-25)+(-15)=(-40)

And the parts are x=(-25), y=(-15)

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Answer 2

Given:

• A number is divided into two parts.
• One part is 10 more than other.
• Two parts are in ratio 5:3.

To Find:

• The two numbers.
• The whole part.

Concept Used :

• We will make supposition and hence find the two parts.

• We will be solving by converting the statements into linear equations.

Answer:

Let us take

• First part be x .
• Second part x+10.

Atq ,

$\sf{\implies\dfrac{x+10}{x}=\dfrac{5}{3}}$

$\sf{\implies3(x+10)=5\times x }$

$\sf{\implies3x+30=5x}$

$\sf{\implies5x-3x=30}$

$\sf{\implies 2x=30}$

$\sf{x=\cancel{\dfrac{30}{2}}}$

${\underline{\red{\sf{\leadsto x =15}}}}$

So ,

• First part = x = 15.
• Second part =x+10=(15+10)=25 .
• Whole part = x+x+10=(15+15+10)= 40 .