Question

a number is divided into two parts such that one part is 10 more than the others.if the two parts are in the ratio of 5:3, find the number and two parts
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Answer 1

$\huge\boxed{Answer}$

Since the two parts are in the ratio 5:3, then let the first number be 5x and second number be 3x. As second number is 10 more than the other, so it will be 3x+10.

5x=3x+10

2x=10

x=5

The first number becomes 5(5)=25 and second number becomes 3(5)=15.

The new number will be 25+15=40.

$\huge\mathfrak\red{itz\:jyotsana☺}$

Answer 2

Answer:

the two part of the number are x and x+10

x+10:x=5:3

x+10/x=5/3

5x=3x+30

5x-3x=30

2x=30

x=30/2=15

so the two parts of the number are 15 and 15+10=25

the number is 25+15=40