Question

A number is divided into two parts such that one part is 10 more than the other. if the two parts are in the ratio 5:3,find the number and the two parts​

Answer 1

Answer:

let the ratio be 5x:3x

let x= the first no.

let 10+x the second no.

ATQ.

x+10+x = 5x+3x

2x = 8x-10

2x + 8x = -10

10x = -10

x = -10/10

x = -1

first no. = x = -1

second no. = 10 + x = 10+(-1) = 9