Question

A number is divided into two parts such that one part is 10 more than the other. If
parts are in the ratio 5:3, find the number and the two parts.​

Answer 1

Answer:

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Answer 2

$\huge {\mathfrak {\underline{\underline{\pink {Answer}}}}}$

$\huge\tt Given :$

• A number is divided into two parts such that one part is 10 more than the other.
• Both parts are in the ratio 5:3.

$\huge\tt To\:Find :$

• the number and the two parts.

$\huge\tt Solution :$

let the common factor be x

Then ,

• first number = 5x
• second number = 3x

Given one part is 10 more than the other ..

So ,

$\tt 5x- 10 = 3x$

$\tt 5x - 3x = 10$

$\tt 2x = 10$

$\tt x = \dfrac {10}{2} = 5$

so the first part = 5 × 5 = 25

second part = 5 × 3 = 15

The number = 25+15 = 40

$\huge\tt Answer :$

• First part = 25
• second part = 15
• Total number = 40

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