Question

a number is divided into two parts such that one part is 10 more than the other . if the two parts are in the ratio 5:3 find the number and the two parts​

Answer 1

Given:

One part of the number is 10 more than the other.

The two parts are in the ratio 5:3.

Find:

The two parts

Solution:

Let one number be x.

Let another number be y.

One part of the number is 10 more than the other.

=> x = y + 10 ......(i).

The two parts are in the ratio 5:3.

=> x/y = 5/3

=> 3x = 5y ........(ii).

Putting the value of x from Eq (i). in Eq (ii).

=> 3(y + 10) = 5y

=> 3y + 30 = 5y

=> 30 = 5y - 3y

=> 30 = 2y

=> 30/2 = y

=> 15 = y

=> y = 15

Putting the value of y in Eq (i).

=> x = y + 10

=> x = 15 + 10

=> x = 25

Hence, the two divided parts are 25 and 15.

I hope it will help you.

Regards.

Answer 2

Answer:

=> 3(y + 10) = 5y

=> 3y + 30 = 5y

=> 30 = 5y - 3y

=> 30 = 2y

=> 30/2 = y

=> 15 = y

=> y = 15

Step-by-step explanation: