Question

A number is divided into two parts such that one part is 10 more than the other. If the two
parts are in the ratio 5:3, find the number and the two parts​

Answer 1

Step-by-step explanation:

Given,

A number is divided into two parts such that one part is 10 more than the other.

Let,

One part is x thus other part is x + 10

Suppose,

The two parts are in the ratio 5:3

So,

x+10/x = 5/3

3x+30 = 5x

3x -5x = – 30

-2x = – 30

x = 15

Thus,

x + 10 = 15 +10 = 25

First part = 15 and second part = 25

Therefore,

The number = 15 + 25 = 40