Question

A number is divided into two parts such that one part is 10 more than the other. if the two parts are in the ratio 5:3 , find the number and the Two parts

Answer 1

Let first and second part of the number be x and y, respectively. Then,

5x+11y=7(x + Y)

=> 11y-7y=7x-5x

=> 4y = 2x

x : y = 2 : 1

Answer 2

hi friend

your question is

A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in the ratio 5:3, find the number and the two parts.

and

here your solution

solution:

       let one part of number = x

           therefore ,  other part of number = x+10

   according to question ,

             x+10/x=5/3

           3(x+10)= 5x

           3x+30 =5x

             30 = 5x -3x

             30 = 2x

     or x=30/2

         x=15

therefore one part of number = 15

and other part = 15+10 =25

hence number = 15+25 =40

thankyou