Question

a number is divided into two parts such that one part is 10 more than the other. if the two parts are in the ratio 5:3.find the numbers​

Answer 1

Given that: A number is divided into two parts such that one part is 10 more than the other.

Two parts are in the ratio 5:3.

Need to find: the numbers

☀Let's say that, the numbers are x, x + 10.

~Here, as we can see generally, ( x + 10 ) will be greater than x. So, the ratio given in question is

x + 10 : x :: 5 : 3.

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ATQ,

$\sf : \: \implies \dfrac{x+10}{x} = \dfrac{5}{3}$

~By cross multiplication.

$\sf : \: \implies 3( x + 10 ) = 5( x )$

$\sf : \: \implies 3x + 30 = 5x$

$\sf : \: \implies 5x - 3x = 30$

$\sf : \: \implies 2x = 30$

$\sf : \: \implies x = \dfrac{30}{2}$

$\boxed{\bf{ x = 15 }} \: \: \bigstar$

T H E R E F O R E,

➡ x = 15

➡ x + 10 = 15 + 10 = 25

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• Henceforth, rhe numbers are 15 and 25.