A number is divided into two parts, such that one part is 10 more than the other. If the two parts are in the ratio 5 : 3, find the number and the two parts.
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Answered by
30
The number is divided in 5:3 ratio.
Let one part be = 5x
other part = 3x
Difference = 10
⇒ 5x - 3x = 10
⇒ 2x = 10
⇒ x = 10/2 = 5
first part, 5x = 5×5 = 25
second part, 3x = 3×5 = 15
the number = 25+15 = 40
Let one part be = 5x
other part = 3x
Difference = 10
⇒ 5x - 3x = 10
⇒ 2x = 10
⇒ x = 10/2 = 5
first part, 5x = 5×5 = 25
second part, 3x = 3×5 = 15
the number = 25+15 = 40
QueenofDCasel:
how come it become 5x-3x why it is not positive
if one part is 10 more than other, then 5x-3x=10.
what is your doubt??
what is your doubt??
ok thanks
Answered by
3
Let the two parts be 5x and 3x
So A.T.Q.
5x=3x+10
5x-3x=10
2x=10
x=5
Two parts are 25 and 15
No. is 25+15=40
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