Question

A number is divided into two parts such that one part is 10more than the other. If the two parts are in the ratio 5:3, find the number

Answer 1

$\textbf{Answer:}$

Let the 1st part = x

Other part be = x+10

According to the question:

$\frac{x + 10}{x} = \frac{5}{3} \\ \\ = > 3(x + 10) = 5x \\ \\ = > 3x + 30 = 5x \\ \\ = > 30 = 5x - 3x \\ \\ = > 30 = 2x \\ \\ = > x = \frac{30}{2} = 15 \\ \\ = > x = 15$

First part = 15


Second part = 15+10=25


Sum of two parts = 40


$\textbf{Hope it helps you!}$

Answer 2

X+10/x=5/3

3(x+10)=5x

3x+30=5x

30=5x-3x

30=2x

X=30/2=15

1 part=15

2 part=15+10

Number =40