Question

A number is divided into two parts, such that one part is 6 less than the other. If the two parts are in the ratio
4:7, find the number and the two parts.
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Answer 1

Answer:

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Step-by-step explanation:

Since the two parts are in the ratio 4:7, then let the first number be 5x and second number be 3x. As second number is 10 more than the other, so it will be 3x+10.

5x=3x+10

2x=10

x=5

The first number becomes 5(5)=25 and second number becomes 3(5)=15.

The new number will be 25+15=40.

Answer 2

Answer:

Let the two parts be 4x and 7x and the number be sum of both parts : (4x + 7x) = 11x

• According to the Question :

⇒ Difference between both parts = 6

⇒ 7x - 4x = 6

⇒ 3x = 6

⇒ x = 6/3

⇒ x = 2

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• Required Number :

⇢ Number = 11x

⇢ Number = 11 × 2

⇢ Number = 22

∴ Hence, the required number is 22.

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• Parts of the number :

⇢ First Part = 4x = (4 × 2) = 8

⇢ Second Part = 7x = (7 × 2) = 14

∴ Hence, two different parts are 8 and 14.