Question

A number is divided into two such that One part is 10 more than the other. If the two parts are in the ratio 5:3, find out the Number​

Answer 1

$\sf\tt\large{\green {\underline {\underline{❀ \: Given:}}}}$

• A number is divided into two parts such that one part is 10 more than the other.

• The two parts are in the ratio 5:3(5/7)

$\sf\tt\large{\green {\underline {\underline{❀ \: To \: find:}}}}$

• The Number.

$\sf\tt\large{\green {\underline {\underline{❀ \:Solution:}}}}$

Let us assume that the one part of the no. be n

and other be n + 10.

From the question,

$\sf \tt{ \frac{n + 10}{n} = \frac{5}{3} }$

$\sf\rightarrowtail{\:\:3(n+ 10) = 5n}$

$\sf\rightarrowtail{\:\:3n + 30 = 5n}$

$\sf\rightarrowtail{\:\:3n + 30 - 5 = 0}$

$\sf\rightarrowtail{\:\: - 2n + 30 = 0}$

$\sf\rightarrowtail{\:\:\cancel- 2n = \cancel - 30}$

$\sf\rightarrowtail{\:\:n= \frac{^{15}{\cancel{30}}}{\cancel{2 \: _1}}}$

$\sf \pink\rightarrowtail \pink{\: \:\pmb{n = 15}}$

Therefore,

One part of no. = n = 15

Other part of no. = n + 10 = 15 + 10 = 25

Number = 10 + 25 = 40.

$\sf\bf {\pink{\large{\underline{H\frak{ence,\: the \: required \: no. \: is \: 40 \: \: \: }}}}}$