Question

A number is divided strictly into two unequal parts such that the difference of the squares of the two parts equals 50 times the difference between the two parts. What is the number?​

Answer 1

Answer:

The number is 50

Step-by-step explanation:

Let the number be A

let it is divided into two unequal parts x and y

Then

A = x + y

According to the question

$x^2-y^2=50(x-y)$

$\implies (x-y)(x+y)=50(x-y)$               [∵ x² - y² = (x+y)(x-y)]

$\implies x+y=50$

or, A = 50

Therefore the number is 50

Hope this helps.