Question

A number is divisble by 11 & 91 what is the sum of the digits of the smallest such number

Answer 1

The answer is given below :

Since, the number is divisible by 11 and 91, to find the number, we need to find the lcm of 11 and 91.

Now, 91 = 1 × 7 × 13 and 11 = 1 × 11

So, the lcm of 11 and 91

= 1 × 7 × 13 × 11

= 1001

So, the smallest such number is = 1001.

Thus, the sum of the digits of the number 1001 is

= 1 + 0 + 0 + 1

= 2

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