Question

A number is divisible by 11 if the difference of the sum of its digits in odd places and the
sum of its digits in even places (starting from the units place) is either 0 or divisible by 11.
Divisibility by 11
Study the following table.
Numbers Sum of the Digits in
Odd Places
Difference
Sum of the Digits in
Even Places
3465
5 + 4 = 9
6 + 3 = 9
9-9 = 0
6457
7 + 4 = 11
5 + 6 = 11
11 - 11 = 0
95986
6 + 9 + 9 = 24
8 + 5 = 13
24 - 13 = 11
280929
9 + 9 + 8 = 26
2+0+2 = 4
26 - 4 = 22
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Answer 1

eg:- 542371

sum of digit = 1+3+4=8

sum of even place =5+2+7= 14

difference =14 -8=6 (not a maltipal of 8)

542371 is not divisibility by 11

Answer 2

In a nutshell, the divisibility rule of 11 states that if the difference between the sums of the given number's alternate digits is either 0 or divisible by 11, the number is divisible by 11.

• These alternate digits are also known as digits in even places and digits in odd places.
• Let us illustrate this with an example.
• If we take the alternate digits in 86416 starting from the right, we get 6, 4, and 8, with the remaining alternate digits being 1 and 6. Now, 6 + 4 + 8 equals 18, and 1 + 6 equals 7. After subtracting these sums, we get 18 - 7 = 11, which is divisible by 11. As a result, 86416 is divisible by 11.

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