Question

a number is divisible by both 13 and 14 By which other's number will that number be always divisible​

Answer 1

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Factors of 5 = 1,5

Factors of 12 = 1, 2, 3, 4, 6, 12

5 and 12 are co-primes, and we know that if a number is divisible by two co-primes, then it is a known fact that it is also divisible by their product.

The product of 5 and 12 is 60. Hence, the number is always divisible by 60.

Answer 2

Answer:

• Answer:
• Answer < /p > < p > < /p > < p > Open in answr app < /p > < p > < /p > < p > Given : 16x4+54x < /p > < p > < /p > < p > We can write the given question as, < /p > < p > < /p > < p > 16x4+54x=2x(8x3+27) < /p > < p > < /p > < p > According to the equation, < /p > < p > a3+b3=(a+b)(a2−ab+b2) < /p > < p > < /p > < p > So we get, < /p > < p > 2x(8x3+27)=2x((2x)3+33) < /p > < p > < /p > < p > Using the equation, < /p > < p > =2x((2x)+3)((2x)2−(2x)(3)+(3)2) < /p > < p > < /p > < p > 16x4+54x=2x(2x+3)(4x2−6x+9) < /p > < p > < /p > < p >Answer</p><p></p><p>Openinanswrapp</p><p></p><p>Given: 16x4+54x</p><p></p><p>Wecanwritethegivenquestionas,</p><p></p><p>16x4+54x=2x(8x3+27)</p><p></p><p>Accordingtotheequation,</p><p>a3+b3=(a+b)(a2−ab+b2)</p><p></p><p>Soweget,</p><p>2x(8x3+27)=2x((2x)3+33)</p><p></p><p>Usingtheequation,</p><p>=2x((2x)+3)((2x)2−(2x)(3)+(3)2)</p><p></p><p>16x4+54x=2x(2x+3)(4x2−6x+9) </p><p></p><p>

Step-by-step explanation:

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