Math, asked by abhishek7234, 1 year ago

a number is divisible by both 3 and 8. by which other numbers will thus number always be divisible? with formula.​

Answers

Answered by wolverine000
45

Answer:

24,48,72,96...

Explanation:

divisible by 3 and 8 are 12×even num

12×2=24

12×4=48

12×6=72

12×8=96....

Answered by Yashraj2022sl
0

Answer:

Therefore, if a number will be divisible by 24 if it can be divided by 3 and 8 simultaneously.

Concept:

If the residual is zero, a number is said to be divisible by another integer in mathematics. A set of broad guidelines known as the "divisibility rules" is frequently used to determine whether or not a number is evenly divisible by another number.

Given:

Considering that a number can be divided by both 3 and 8.

To find:

A different integer that always divides the given number.

Calculation:

Let n number is divisible by both 3 and 8.

Factors of 3 are 1 and 3.

Factors of 8 are 1,2,4 and 8.

As we can see 3 and 8 share no other common factors, they are co-primes, and we know that if a number can be divided by two co-primes, it can also be divided by the product of those two co-primes.

Using the condition that 3 and 8 are co-prime numbers, n is divisible by (3 x 8), or 24.

Hence, if a number will be divisible by 24 if it can be divided by 3 and 8 simultaneously.

#SPJ2

Similar questions