a number is divisible by both 3 and 8. by which other numbers will thus number always be divisible? with formula.
Answers
Answer:
24,48,72,96...
Explanation:
divisible by 3 and 8 are 12×even num
12×2=24
12×4=48
12×6=72
12×8=96....
Answer:
Therefore, if a number will be divisible by 24 if it can be divided by 3 and 8 simultaneously.
Concept:
If the residual is zero, a number is said to be divisible by another integer in mathematics. A set of broad guidelines known as the "divisibility rules" is frequently used to determine whether or not a number is evenly divisible by another number.
Given:
Considering that a number can be divided by both 3 and 8.
To find:
A different integer that always divides the given number.
Calculation:
Let n number is divisible by both 3 and 8.
Factors of 3 are 1 and 3.
Factors of 8 are 1,2,4 and 8.
As we can see 3 and 8 share no other common factors, they are co-primes, and we know that if a number can be divided by two co-primes, it can also be divided by the product of those two co-primes.
Using the condition that 3 and 8 are co-prime numbers, n is divisible by (3 x 8), or 24.
Hence, if a number will be divisible by 24 if it can be divided by 3 and 8 simultaneously.
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