Question

A number is divisible by both 3 and 8. By which other numbers will that number be always divisible?

Answer 1

Step-by-step explanation:

• 24,48,72,96

Explanation:

Rule:-

divisible by 3 and 8 are 12×even num

• 12×2=24

• 12×4=48

• 12×6=72

• 12x8=96

Required answer:-

96

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Answer 2

Answer:

The answer to this question is 1, 2, 4, 6, 12, 24

Step-by-step explanation:

So, we know that number is divisible by 3 and 8 so first We will find the highest no. possible to be divisible by 3 and 8 by multiplying the given two numbers

So according to the above statement,

3*8=24

So, 24 is the highest possible number which is divisible by 3 and 8.

So now we will find the numbers which are divisible by 24 which are

1, 2, 4, 6, 12, 24

So, The numbers which are divisible by 24, will be divisible by 3 and 8 also

Therefore, answer is 1, 2, 4, 6, 12, 24.

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