Question

A number is divisible by both 7 and 10. By what other numbers will it be always divisible?​

Answer 1

Answer:

the no is divisible by

1, 2, 5, 7, 10, 14, 35 and 70.

Answer 2

Answer:

As 7 and 13 are distinct primes, their GCD is 1, and hence LCM(7,13)=7×13/GCD(7,13)=91/1=91. Hence the set of all divisors of the given number are all the integer multiples of 91.