A number is doubled to get a second number which is further doubled to get a third number. When these three numbers are added, it is found that the sum is 8 less than 8 times the original number. Find the original number
Answers
Answered by
2
Given :-
A number is doubled to get a second number which is further doubled to get a third number. When these three numbers are added, it is found that the sum is 8 less than 8 times the original number
To Find :-
Original number
Solution :-
Let the original number be x
Now
When the original number is doubled than the second number will be formed.
Second number = 2x
When the second number is doubled the third number is formed
Third number = 2x × 2
Third number = 4x
Their sum is 8 less than 8 times of original number
Original number is x. So,
8x - 8 = x + 2x + 4x
8x - 8 = 7x
- 8 = 7x - 8x
- 8 = - x
8 = x
Hence
Original number is 8
[tex][/tex]
Answered by
83
- A number ia doubled to get a second number which is further doubled to get a third number.when these three numbers are added, it is found that the sum is 8 less than 8 times the original number.
- All three numbers.
- Let the number be x.
- Then 2nd number is 2x and the third number is 4x.
By the condition,
( x + 2x + 4x ) + 8 = 8x
or, 7x + 8 = 8x
So, the 1st, 2nd and 3rd numbers are 8,16,32 respectively.
Hence, the answer is the numbers are 8,16 and 32.
Similar questions