Question

A number is doubled to get a second number which is further doubled to get a third number. When these three numbers are added, it is found that the sum is 8 less than 8 times the original number. Find the original number​

Answer 1

Given :-

A  number is doubled to get a second number which is further doubled to get a third number. When these three numbers are added, it is found that the sum is 8 less than 8 times the original number

To Find :-

Original number

Solution :-

Let the original number be x

Now

When the original number is doubled than the second number will be formed.

Second number = 2x

When the second number is doubled the third number is formed

Third number = 2x × 2

Third number = 4x

Their sum is 8 less than 8 times of original number

Original number is x. So,

8x - 8 = x + 2x + 4x

8x - 8 = 7x

- 8 = 7x - 8x

- 8 = - x

8 = x

Hence

Original number is 8

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Answer 2

$\boxed{\boxed{\huge{\blue{\bold{\underline{Given:-}}}}}}</p><p>$

• A number ia doubled to get a second number which is further doubled to get a third number.when these three numbers are added, it is found that the sum is 8 less than 8 times the original number.

$\boxed{\boxed{\huge{\blue{\bold{\underline{To Find :-}}}}}}$

• All three numbers.

$\boxed{\boxed{\huge{\blue{\bold{\underline{Solution :-}}}}}}$

• Let the number be x.

• Then 2nd number is 2x and the third number is 4x.

By the condition,

( x + 2x + 4x ) + 8 = 8x

or, 7x + 8 = 8x

$\fbox\pink{∴ \: x = 8}$

So, the 1st, 2nd and 3rd numbers are 8,16,32 respectively.

Hence, the answer is the numbers are 8,16 and 32.