A NUMBER IS EIGHT MORE THAN THREE TIMES OF THE OTHER NUMBER .IF THEIR SUM IS 12.FIND THE NUMBERS
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let 3x+8 and 3x be the first and second number respectively
by question
3x+8 + 3x = 12
3x+3x+8=12
6x+8=12
6x=12-8
6x=4
x=4/6
x=⅔
then,
first number=3x+8 = 3×⅔+8 = 2+8 = 10
the second number = 3x= 3×⅔ = 2
checking
10+2=12
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