Question

A number is first increased by 10% and then it is further increased by 20%. The original number is increased altogether by:

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Answer 1

Answer:

32%

Step-by-step explanation:

Let the number be x.

1. Increased by 10%

$\displaystyle x + \frac{10}{100}x = \frac{110}{100}x$

2. Increased by 20%

$\displaystyle \frac{110}{100}x +\left(\frac{20}{100} \times \frac{110}{100}x\right)\\\\= \frac{132}{100}x$

% increase:

$\displaystyle \frac{\frac{132}{100}x - x}{x} \times 100\\\\= 32\%$

Answer 2

Answer:

8 percent

Step-by-step explanation:

Let the number be x

Then 10 percent of x = x/10

There fore it is reduced by x- x/10 = 9x/ 10.

Now 20 percent of the new number, 9x/10 is 20/100 ×9x/10

= 9x/ 50.

There fore it is increased by 9x/10 + 9x/50 = 54x/10

Now this is 8 percent more than x.