Question

A number is first increased by 10℅and then reduced by 10℅.he number:
(a)does not changes
(b)decreases by 1℅
(c) increases by 1℅
(d)none of these
Choose the right answer and explain how???

Answer 1

Let the number be 100.

● First increase it by 10%

10% of 100 = 100 × 10/100 = 10

it will become = 100 + 10 = 110

● Now reduce it by 10%

10% of 110 = 110.× 10/100 = 11

it will become = 110 - 11 = 99

==========================

initial number = 100

finally we got = 99

decrease = 100 - 99 = 1

% decrease = 1/100 × 100 = 1%

Thus it decreases by 1%.

answer is b.

Answer 2

${\huge {\bold {\mathfrak {hey}}}}$

$\underline \bold {Let \: The \: Number \: Be \: 100}$

➡️ The number is 1st increase by 10%

▶️10% of hundred = 100 × 10/100 10

It will becomes = 100 + 10 = 110.

➡️ ➡️ Then it is reduce by 10%

▶️ 10% of 110 = 110 × 10/100 = 11

Then it will becomes = 110 - 11 = 99

Now,

Initial number = 100
The number we get = 99

Therefore,
Decrease = 100 - 99 = 1

% of decrease = 1/ 100 × 100 = 1%

▶️ ▶️▶️➡️▶️➡️▶️➡️▶️➡️▶️➡️▶️➡️➡️▶️➡️▶️

$\huge \bold {OPTION \: B}$

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HOPE IT WILL HELP YOU

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BE BRAINLY

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