Math, asked by shivasharma1, 1 year ago

A number is first increased by 20℅ and then decreased by 15℅ find the net increase or decrease percent.

Answers

Answered by Anonymous
1
Net increase= increase%-decrease%
=20%-15%
=5%
Answered by Anonymous
1
ANSWER = 2 % 


---------- EXPLANATION --------------



Let the required number be 100

Now, according to the question.

The number is first increased by 20 %

⇒ 100 + 20 % of 100

⇒ 100 + [(20*100)/100] 

⇒ 100 + 20

⇒ 120

Then, it is decreased by 15 %

⇒ 120 - (15 % of 120)

⇒ 120 - [(15*120)/100]

⇒ 120 - 18

= 102

Net increase = 102 - 100

= 2

Percent increase = (Change in number*100)/100

⇒ (2*100)/100 

= 2 %

Hence, the increase percent is 2 %.
Similar questions