A number is first increased by 20℅ and then decreased by 15℅ find the net increase or decrease percent.
Answers
Answered by
1
Net increase= increase%-decrease%
=20%-15%
=5%
=20%-15%
=5%
Answered by
1
ANSWER = 2 %
---------- EXPLANATION --------------
Let the required number be 100
Now, according to the question.
The number is first increased by 20 %
⇒ 100 + 20 % of 100
⇒ 100 + [(20*100)/100]
⇒ 100 + 20
⇒ 120
Then, it is decreased by 15 %
⇒ 120 - (15 % of 120)
⇒ 120 - [(15*120)/100]
⇒ 120 - 18
= 102
Net increase = 102 - 100
= 2
Percent increase = (Change in number*100)/100
⇒ (2*100)/100
= 2 %
Hence, the increase percent is 2 %.
---------- EXPLANATION --------------
Let the required number be 100
Now, according to the question.
The number is first increased by 20 %
⇒ 100 + 20 % of 100
⇒ 100 + [(20*100)/100]
⇒ 100 + 20
⇒ 120
Then, it is decreased by 15 %
⇒ 120 - (15 % of 120)
⇒ 120 - [(15*120)/100]
⇒ 120 - 18
= 102
Net increase = 102 - 100
= 2
Percent increase = (Change in number*100)/100
⇒ (2*100)/100
= 2 %
Hence, the increase percent is 2 %.
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