A number is first increased by 20% and then decreased by 15%. Find the net increase or
decrease percent.
Answers
Answered by
1
Solution :-
Let the required number be 100
Now, according to the question.
The number is first increased by 20 %
⇒ 100 + 20 % of 100
⇒ 100 + [(20*100)/100]
⇒ 100 + 20
⇒ 120
Then, it is decreased by 15 %
⇒ 120 - (15 % of 120)
⇒ 120 - [(15*120)/100]
⇒ 120 - 18
= 102
Net increase = 102 - 100
= 2
Percent increase = (Change in number*100)/100
⇒ (2*100)/100
= 2 %
Hence, the increase percent is 2 %.
Answer.
Hope this will help you.
Let the required number be 100
Now, according to the question.
The number is first increased by 20 %
⇒ 100 + 20 % of 100
⇒ 100 + [(20*100)/100]
⇒ 100 + 20
⇒ 120
Then, it is decreased by 15 %
⇒ 120 - (15 % of 120)
⇒ 120 - [(15*120)/100]
⇒ 120 - 18
= 102
Net increase = 102 - 100
= 2
Percent increase = (Change in number*100)/100
⇒ (2*100)/100
= 2 %
Hence, the increase percent is 2 %.
Answer.
Hope this will help you.
Answered by
0
Quick-
(20-15)-(20*15)/100%
=(5-3)%
=2%
Hence net decrease percentage=12%
Please mark me as Brainlist.
(20-15)-(20*15)/100%
=(5-3)%
=2%
Hence net decrease percentage=12%
Please mark me as Brainlist.
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