Question

A number is first increased by20% and then decreased by 20%.Find the net increase or decrease percent.​

Answer 1

Answer:

4% decrease

Step-by-step explanation:

Let the number be x

after the first increase

$x \times (1 + \frac{20}{100} ) = 1.2x$

After the next decrease it becomes

$1.2x(1 - \frac{20}{100} ) = 1.2x \times .8 = .96x$

hence percentage decrease is

$x - .96x = .04x$

4% decrease

Answer 2

4% ANSWER

Step-by-step explanation:

Let us suppose the number to be x.

As per the first case, the number is increased by 20%

Hence: x+ ((x*20)/100)

Resultant number is ‘6x/5’

As per the second case, resultant number is then decreased by 20%

Hence : (6x/5) - (((6x/5) * 20)/100)

Which is (6x/5) - (6x/25) = 24x/25.

The original number being x, we witness a net decrease in the overall process as (24x/25) is less than x.

Therefore Net decrease_

x - (24x/25)= x/25

Net decrease in percentage= (Net Decrease/ Initial Value) * 100%

Thus, ((x/25)/x) * 100% = 4%

So, the answer is 4%.

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