Question

A number is greater than 5 times of its reciprocal by 19/2. find the number​

Answer 1

Answer:

Hope it helps............

Answer 2

Answer:

10 ( or - 1 / 2 )

Step-by-step explanation:

Let the number be x. so, it's reciprocal will be 1/x.

Now,

x = 5(1/x)+ 19/2

x = 5/x + 19/2

Multiplying with denominators on opposite sides, we get,

x = 10+19x/ 2x

2x² = 10+19x

2x²-19x-10=0

2x²-20x+1x-10=0

2x(x-10)+1(x-10)=0

(2x+1)(x-10)=0

x=-1/2 or x = 10