A number is greater than another by 17 and their sum is 43 find the numbers
Answers
Answered by
1
let one number be x
other number is x+17
hence,
B/Q
x+x+17=43
=2x=43-17
=2x=26
=x=26/2
=x=13
hence,
First no.=13
Other no.=13+17
=30
other number is x+17
hence,
B/Q
x+x+17=43
=2x=43-17
=2x=26
=x=26/2
=x=13
hence,
First no.=13
Other no.=13+17
=30
darmaraj:
thanks
Answered by
1
let one number be x and another be x+17
now,ATQ
x+x+17=43
2x+17=43
2x=43-17
2x=26
x=13
so first no. will be 13 and another will be 13+17=30.
hope it helped.......
now,ATQ
x+x+17=43
2x+17=43
2x=43-17
2x=26
x=13
so first no. will be 13 and another will be 13+17=30.
hope it helped.......
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