Question

A number is greater than the average of its third, quarter and one twelfth. Find it.

Answer 1

let the number be x
$x> \frac{1}{3}( \frac{x}{3}+ \frac{x}{4}+\frac{x}{12}) \\ x> \frac{8x}{12(3)} \\ x> \frac{2x}{9}$
so all numbers satisfy this condition
so it can be any number
If it is equal then the number is zero