Question

A number is increased by 10% and then decreased by 10%. Find the net increase or
decrease per cent.​

Answer 1

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Answer 2

$\huge{ \text{ \purple{ \underline{ \underline{✿Solution!}}}}}$

$\sf{Let \: the \: number \: is \: increased \: by \: 10\%}$

$\sf{x+ \frac{10x}{100} = \frac{11}{10} }$

$\sf{The \: number \: is \: decreased \: by 10 \%} \\ \sf{= \frac{11x}{10} − \frac{11x}{10} × \frac{10}{100} } \\ \sf{= \frac{11x}{10} − \frac{11x}{100} = \frac{99x}{100} }$

$\sf{Decrease \: in \: percentage \: is }</p><p> \sf{Decrease =x− \frac{99x}{100} = \frac{x}{100} }$

$\sf{so \: decreased \: by \: \%}$

$\sf{= \frac{ \frac{x}{100} }{x} ×100\%=1\%}$

$\mathcal{ \blue{ \boxed{ \therefore{The \: answer \: is \: 1\%}}}}$

Hope you this helps you mate! ✌