Question

A number is increased by 10% and then the increased number is deceased by 10%. Find the net increase or decrease percent ?

Answer 1

Solution :-


⊙ Let the number be x

⊙ Increased number = 110% of x

=
$(x \times \frac{110}{100} ) = \frac{11x}{10}$


⊙ Decreased number =
$90\% \: of \: ( \frac{11x}{10} )$



=
$( \frac{11x}{10} \times \frac{90}{100} ) = \frac{99x}{10}$



Net decrease =

$(x - \frac{99x}{100} ) = \frac{(100x - 99x)}{100} = \frac{x}{100}$


Net decrease percentage :-


$( \frac{x}{100} \times \frac{1}{x} \times 100)\% = 1\%$




Hope it helps you


$<big><b > prabhudutt$