Question

A number is increased by 20% and decreased by 20% , find the net increase or decrease​

Answer 1

Answer:

Let us suppose the number to be x.

As per the first case, the number is increased by 20%

Hence: x+ ((x*20)/100)

Resultant number is ‘6x/5’

As per the second case, resultant number is then decreased by 20%

Hence : (6x/5) - (((6x/5) * 20)/100)

Which is (6x/5) - (6x/25) = 24x/25.

The original number being x, we witness a net decrease in the overall process as (24x/25) is less than x.

Therefore Net decrease_

x - (24x/25)= x/25

Net decrease in percentage= (Net Decrease/ Initial Value) * 100%

Thus, ((x/25)/x) * 100% = 4%

So, the answer is 4%.

Answer 2

Answer:

= 4%

Step-by-step explanation:

Let the number be =100

Increase in the number =20% of 100

=

100

20

×100

=20

Increased number =100+20

=120

The resulting number decreased by 20%

Decrease in the number =

120

20

×120

=24

New number =120−24

=96

Now, net decrease =100−96

Net % decrease =

Original number

Net decrease

×100

=

100

4

×100

=4%

Hence the net percent decrease is 4%.