Question

A number is increased by 20% and the increased number is decreased by 20%. Find the net increase of decrease per cent.​

Answer 1

Answer:

0%

Step-by-step explanation:

the increased% is 20% and decreased% is also 20% so the net increase is 0%......

Answer 2

Answer:

Let us suppose the number to be x.

As per the first case, the number is increased by 20%

Hence: x+ ((x*20)/100)

Resultant number is ‘6x/5’

As per the second case, resultant number is then decreased by 20%

Hence : (6x/5) - (((6x/5) * 20)/100)

Which is (6x/5) - (6x/25) = 24x/25.

The original number being x, we witness a net decrease in the overall process as (24x/25) is less than x.

Therefore Net decrease_

x - (24x/25)= x/25

Net decrease in percentage= (Net Decrease/ Initial Value) * 100%

Thus, ((x/25)/x) * 100% = 4%

So, the answer is 4%.

Step-by-step explanation:

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