A number is increased by 20%and then decreased by20% the final value of the number
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Let the original number be ' x '.
Given that first it is increased by 20 %, therefore,
x + 20 % of x
=> x + 20x/100
=> x + 2x/10
=> x + 0.2 x
=> 1.2 x
Hence, new number = 1.2 x
Now it is given that the number is decreased by 20 %, therefore,
1.2 x - 20 % of 1.2 x
=> 1.2 x - ( 20 * 1.2x ) / 100
=> 1.2 x - 24x/100
=> 1.2 x - 0.24 x
=> 0.96 x
Hence, final number = 0.96 x
Therefore, final number will be 0.96 time of the original number.
Given that first it is increased by 20 %, therefore,
x + 20 % of x
=> x + 20x/100
=> x + 2x/10
=> x + 0.2 x
=> 1.2 x
Hence, new number = 1.2 x
Now it is given that the number is decreased by 20 %, therefore,
1.2 x - 20 % of 1.2 x
=> 1.2 x - ( 20 * 1.2x ) / 100
=> 1.2 x - 24x/100
=> 1.2 x - 0.24 x
=> 0.96 x
Hence, final number = 0.96 x
Therefore, final number will be 0.96 time of the original number.
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